Objective: Students will create scatter plots given data in a table. Students will then do regressions to model the data.

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Objective: Students will create scatter plots given data in a table. Students will then do regressions to model the data. About the Lesson: Homestead-Miami Speedway has been rebuilt in different configurations more often than any other track on the NASCAR circuit. Originally built as part of the Hurricane Andrew (1992) recovery efforts, the track opened in 1995 as a 60% version of the Indy 500, a rectangle with round corners; reflecting the fact that in 1995 the dominant form of motor sports in the US was still Indy Cars. The flat 6 degree banking and short straights made for single groove (boring) racing and treacherous crash angles in the corners. You can still race (digitally) this original layout by going to some on-line racing sites. The track was widened in 1996 to alleviate some of its racing issues, but not very successfully, so the track was rebuilt again as a traditional oval in 1997; however, still with relatively flat low banked turns. Finally in 2003 the track was rebuilt once more but with the current progressive 18 to 20 degree banking allowing for multi-groove racing and more passing. In this activity you will investigate turn radii and banking as part of the drive path around this track. Drivers have to decide if it is better to go faster or take the shortest path. Can you decide? Materials: Student Worksheet Prerequisite skills: The students need to be familiar with all family of graphs including exponentials. Students also need basic trigonometry skills. Analysis: Using TI-Nspire Technology 1. Open the file named Homestead_Chase_Activity.tns. 2. Move to page 1.2. Driving on a larger radius path around a curve allows a car to go faster, but the path is longer. The force required to impart the centripetal acceleration to turn the car onto a radius of r is given by the formula first developed by Christian Huygens, circa 1657.

3. The data in the spreadsheet shows the maximum speed in ft/sec at different radii in ft. 4. Move to page 1.3 to create a scatter plot of speed vs. radius. 5. What is the independent variable? Answer: Radius 6. What is the dependent variable? Answer: Speed Navigator Tip: Quick Poll the students for their answers to #5 and #6 and show the results to make sure the students know which variable goes on which axis. 7. Press h and choose your independent variable. Press then h and select your dependent variable. Press. 8. Press b then Window/Zoom > Zoom Data. Page 2 of 8

9. The data is not linear. What type of function do you think this is? Answer: Answers may vary, but it is actually power function. 10. Find a model for the data by doing a regression. Move back to page 1.2 and move to column C. 11. Press b then choose Statistics > Stat Calc and choose the model you think best represents the data. 12. Fill in the form with the appropriate independent and dependent variables and leave the other boxes as the default settings. 13. Move to page 1.3. 14. Press b > Graph Type > Function. The function bar will appear at the bottom of the screen. Press to see f1(x) and press. Your curve for single power should appear. 15. Press e then to see f1(x) and press to see your curve. 16. Did your model fit the data? If not repeat steps 11-15 for a different type of function. What is your equation? Answer: The equation should be approximately y=5.08x 0.5. Navigator Tip: Quick Poll the students for their answers to #16 and show the results to start a good discussion about models. The issue is made more complex with track banking. Up to a banking angle of 45 degrees there is a maximum speed that a car can travel around a curve without sliding up the track and into the fence. On a banked track a portion of the force producing centripetal acceleration also adds to the down force on the car, thus increasing its traction on the track. Page 3 of 8

The extra variable θ changes the equation to v = (((32.17*r(0.8*cos θ+sin θ))/(cos θ- 0.8*sin θ)))^(0.5) where 32.17 is the gravitational constant and 0.8 is the coefficient of friction. 17. Move to page 1.4. The Homestead-Miami track features progressive banking in the corners going from 18 to 20 degrees, so moving higher on the track allows a car to go faster due to both banking and an increase in curve radius. Assume for each half degree in banking the car is running on a path that is 15' larger in radius starting at r = 500' for the 18 degree banking. 18. Compare the speed for the 18 degree banking and the speed for no banking from your model at a radius of 500. Answer: Answers will vary but 131 ft/sec compared to 114 ft/sec is a 17 ft/sec increase in speed for the banking. 19. Now compare two drivers going around the track on the same turn. One car decided to take the 18 degree banking part of the turn, but the other car decides to take the 19 degree part of the turn. Which one has the higher speed? Answer: The car on the 19 degree banking. 20. Which car has to drive the shortest distance? Answer: The car on 18 degree banking. Page 4 of 8

It is a trade off between speed and distance. The shorter path is only faster if the tires can hold the car around the tighter radius at a higher speed. Also the car on the shorter path must also brake earlier than the car on the outside. The key is to have the quickest time around the turn. That is what makes a NASCAR driver a professional. Using spreadsheet software Driving on a larger radius path around a curve allows a car to go faster, but the path is longer. The force required to impart the centripetal acceleration to turn the car onto a radius of r is given by the formula first developed by Christian Huygens, circa 1657. Radius (ft) Speed (ft/sec) 300 87.90904 350 94.95262 400 101.5086 450 107.6662 500 113.4901 550 119.0294 600 124.3222 700 134.2833 1. Enter the data from the table into spreadsheet software. 2. Use the chart wizard to create a scatter plot of speed vs. radius led for each driver. Chart type will be XY(Scatter). Click Next. 3. What is the independent variable? Answer: Radius Page 5 of 8

4. What is the dependent variable? Answer: Speed 5. You will have to click on the Series tab to make sure the correct data is on the correct axis. If the wrong data is there, click in the box for the x values then highlight the data for the independent variable. 6. Repeat step 5 for the y values. Click Next. 7. Create titles for the chart and each axis. You can also click the other tabs to change the appearance of your graph. Click Next. 8. Decide if you want the graph to appear in the same window as your table or in a new window. Click Next and your graph should appear. 9. The data is not linear. What type of function do you think this is? Answer: Answers may vary, but it is actually power function. 10. Create a model of the data next. Right click on the data and select Add Trendline. Choose the type of function you chose from question 9. Click the Options tab and click the box beside Display equation on chart. Click OK. 11. Did your model fit the data? If not right click on the trend line and change the type of function. Repeat this step until your model fits the data. What is your equation? Answer: The equation should be approximately y=5.08x 0.5. The issue is made more complex with track banking. Up to a banking angle of 45 degrees there is a maximum speed that a car can travel around a curve without sliding up the track and into the fence. On a banked track a portion of the force producing centripetal acceleration also adds to the down force on the car, thus increasing its traction on the track. Page 6 of 8

The extra variable θ changes the equation to v = (((32.17*r(0.8*cos θ+sin θ))/(cos θ- 0.8*sin θ)))^(0.5) where 32.17 is the gravitational constant and 0.8 is the coefficient of friction. The Homestead-Miami track features progressive banking in the corners going from 18 to 20 degrees, so moving higher on the track allows a car to go faster due to both banking and an increase in curve radius. Assume for each half degree in banking the car is running on a path that is 15' larger in radius starting at r = 500' for the 18 degree banking. 12. Use the following data to create a model of speed vs. banking angle. Banking Angle (degrees) Speed (ft/sec) 18 131.2432 18.5 133.5766 19 135.8864 19.5 138.1735 20 140.4384 13. Use the chart wizard to create a scatter plot of speed vs. radius led for each driver. Chart type will be XY(Scatter) with smoothed lines. Click Next. 14. What is the independent variable? Answer: Banking Angle 15. What is the dependent variable? Answer: Speed Page 7 of 8

16. You will have to click on the Series tab to make sure the correct data is on the correct axis. If the wrong data is there, click in the box for the x values then highlight the data for the independent variable. 17. Repeat step 16 for the y values. Click Next. 18. Create titles for the chart and each axis. You can also click the other tabs to change the appearance of your graph. Click Next. 19. Decide if you want the graph to appear in the same window as your table or in a new window. Click Next and your graph should appear. 20. Compare the speed for the 18 degree banking and the speed for no banking from your model at a radius of 500. Answer: Answers will vary but 131 ft/sec compared to 114 ft/sec is a 17 ft/sec increase in speed for the banking. 21. Now compare two drivers going around the track on the same turn. One car decided to take the 18 degree banking part of the turn, but the other car decides to take the 19 degree part of the turn. Which one has the higher speed? Answer: The car on the 19 degree banking. 22. Which car has to drive the shortest distance? Answer: The car on 18 degree banking. It is a trade off between speed and distance. The shorter path is only faster if the tires can hold the car around the tighter radius at a higher speed. Also the car on the shorter path must also brake earlier than the car on the outside. The key is to have the quickest time around the turn. That is what makes a NASCAR driver a professional. Page 8 of 8