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Pre-Lab Quiz / PHYS 224 Ohm s Law and Resistivity Your Name Lab Section 1. What do you investigate in this lab? 2. When 1.0-A electric current flows through a piece of cylindrical copper wire, the voltage drop is 5.38 mv. What is the electric resistance of the wire? 3. If the cylindrical copper wire has a diameter of 0.10 cm, calculate its cross-sectional area. 4. If the cylindrical copper wire is 24 cm long, calculate its resistivity. 1

Lab Report / PHYS 224 Ohm s Law and Resistivity Your Name Lab Section Objective In this lab you will investigate Ohm s law and measure the electric resistivity of metallic wires. Background Ohm s law is an empirical relationship between the voltage and the electric current for materials. For a piece of material, its resistance is defined as RR = VV II, (1) where I (S.I. unit: ampere (A) = coulomb-per-second) is the current flowing through it and V (S.I. unit: volt (V)) is the voltage applied over it. The S.I. unit for resistance is ohm (Ω). For a piece of material, if its resistance is constant over a wide range of voltage (more accurately, over a wide range of electric field) such that RR = VV II = cccccccccccccccc, (2) the material is described as ohmic and follows the empirical Ohm s law. Otherwise, it is called non-ohmic. Most metallic materials such as brass, copper, and stainless steel are ohmic. For a piece of ohmic material, the resistance, R, is the simple linear proportionality between V and I. The resistance, R, depends on the nature and on the specific shape and size of the material. For a wire of length L and uniform cross-sectional area A, 2

RR = ρρ LL AA, (3) where ρρ is the resistivity of the material. Therefore, Ohm s law essentially states that the resistivity of an ohmic material is constant over a wide range of voltage (more accurately, over a wide range of electric field). The S.I. units for Equation (3) are: ρ in ohm-meter (Ω mm); L in meter (mm); A in square meter (mm 2 ); R in ohm (Ω). EXPERIMENT Apparatus Figure 1 displays the set-up used in this lab. The DC power supply can output DC voltages from 0 to (about) 18 V at increments of 0.1 V. A conducting wire to-be-studied in this experiment will be connected in series with a variable resistor. The resistance of the variable resistor will be set at about 18.0 Ω. Caution: to prevent high currents, always initially set the resistance of the variable resistor above 18.0 Ω and then slowly reduce it to get the current you need (1.0 A). To determine the resistance for a specific segment of the wire under study, the voltage across it will be measured by connecting a voltmeter in parallel with the wire segment. The power supply already includes an ammeter in series to measure the current flowing through the circuity. Ohm s law: To demonstrate Ohm s law, you will measure several sets of voltage drop across a stainless steel wire and the corresponding current through it. You will plot VV-versus-II and use 3

Equation (2) to fit the curve. Resistance versus the length of the wire: You will set the current through a stainless steel wire at 1.0 A and will measure the corresponding voltage across a segment of the wire with lengths ll decreasing from LL 0 to 0. You will plot (VV/II)-versus-ll and will use Equation (3) to fit the curve. You will use the obtained slope and the known cross-sectional area of the wire to calculate the resistivity. Resistance versus the cross-sectional area of the wire: You will use four brass wires with different cross-sectional areas (A). You will measure the resistances of all the wires. You will plot (V/I)-versus-(1/A) and use Equation (3) to fit the curve. Procedures 1. Set up the circuit (Figure 1) Keep the power supply in the off position. In this lab, two multi-meters are used. Use one as ammeter and the other as voltmeter. Initially set them at the appropriate sensitivity levels. i) Connect the positive lead of the power supply to the fixed terminal of the variable resistor. ii) Move the slider terminal of the variable resistor to make its resistance initially slightly above 18 Ω. The wire-slide apparatus has four connections. iii) Connect the slider terminal of the variable resistor to the positive power connector (red) of the wire-slide apparatus. iv) Now, connect the negative power connector (black) of the wire-slide apparatus to the ground of the DC power supply. Next, v) connect the positive lead of the voltmeter to the slider probe of the wire-slide apparatus and its ground lead to the reference probe. Thus, the voltmeter is now connected in parallel with the tobe-measured wire. Ask your TA to check the circuit! Note: The wire-slider apparatus has a 2-A fuse. Do not run current over 1.5 A through it. 4

Moreover, constant large current will heat up the wire and increase its resistivity. 2. Install the stainless steel wire Slide the reference probe and the slider probe to their corresponding end positions, so they are parked on the ramps and do not hinder wire insertion. Loosen both wire clamps. The two alignment lines marked near the two wire clamps are used to guide wire insertion. Now, insert the dark gray stain-steel wire through the front of the left-hand clamp and through the back of the right-hand clamp. Tighten both clamps to secure the wire in place. 3. Ohm s law Move the reference probe of the wire-slider apparatus to the 0 cm mark. Move the slider probe to the 24 cm mark. Turn on the power supply. On the power supply, turn the voltage knob clockwise to the end. Then, turn the current knob clockwise very slowly, until the ammeter reads at 1.0 A. If the reading is still below 1.0 A, even when the current knob is turned clockwise to the end, slowly reduce the resistance in the variable resistor (ask your TA how to do this) until you read 1.0 A. When the current reads at 1.00 A, record the voltage across the wire measured by the voltmeter in Table 1. Next, turn the voltage knob counter-clockwise to set the current (measured by the ammeter) in turn to 0.9, 0.8, 0.7, 0.6, 0.5, 0.4, 0.3, 0.2, 0.1 A, read the corresponding voltages across the wire on the voltmeter (Note: the voltage reading on the voltmeter may use the unit of mv) and record the data in Table 1. TABLE 1 The 24-cm-long stainless-steel wire I (A) V (mv) I (A) V (mv) 1.00 0.50 0.90 0.40 5

0.80 0.30 0.70 0.20 0.60 0.10 4. Resistance-versus-length for the brass wire of 0.040 inches in diameter Turn off the power supply. Move the reference probe and the slider probe of the wire-slider apparatus to their corresponding end positions. Loosen the clamp and remove the stainless-steel wire. Following step 2, install the brass wire (yellow) of diameter DD = 0.040 inches (the second thickest brass wire). Move the reference probe of the wire-slide apparatus to the 0 cm mark, and move the slider probe initially to the 24 cm mark. Turn on the power supply. Follow the procedures described in step 3 to set the current measured by the ammeter to 1.0 A. Read the voltage across the wire segment using the voltmeter and record in Table 2. Next, move the slider probe of the wire-slide apparatus in turn to the 20, 16, 12, 8, 4-cm mark (note: the current reading on the ammeter should not change), measure the corresponding voltages across the wire segment using the voltmeter and record in Table 2. Calculate the corresponding resistance for each case. TABLE 2 The brass wire of diameter DD = 00. 000000 l (cm) I (A) V (mv) R (Ω) 24 1.0 20 1.0 16 1.0 12 1.0 8 1.0 4 1.0 6

5. Resistance-versus-diameter for the brass wires of different diameters Repeat the above measurement in turn for the brass wires with diameters DD = 0.050, 0.032, and 0.020 inches, set the length at ll = 24 cm and II = 1.0 A. Record the corresponding voltages in Tables 3. TABLE 3 The 24-cm-long brass wires D (in) I (A) V (mv) R (Ω) A (m 2 ) 1/A (m -2 ) 0.050 1.0 0.040 1.0 0.032 1.0 0.020 1.0 Analysis 1. The 24-cm-long stainless-steel wire Use the data in Table 1, plot the V-versus-I curve. Use Equation (2) to fit the curve and determine the resistance RR = The diameter of the wire is D=0.040 in. Calculate the crosssectional area (1 inch = 2.54 cm) = ππ DD2. Use Equation (3) to calculate the resistivity: ρρ = 4 2. Four brass wires For each wire, calculate the cross-sectional area (1 inch = 2.54 cm) AA = ππ DD2 and record the A values in Tables 3 and 4. For the brass 4 wire of 0.040-in diameter, plot the RR-versus-ll curve and use Equation (3) to fit the curve and record the RR/ll slope in Table 4, use the obtained slope and Equation (3) to calculate the resistivity of brass and record it in Table 4. 7

TABLE 4 0.040-in-diameter brass wire D (in) slope A (m 2 ) ρ (Ω m) 0.040 For each wire, calculate its resistance at 24 cm and calculate the 1/AA value. Record them in Tables 3. Plot the RR-versus-1/AA curve. Record the RR AA slope in Table 5, and use the obtained slope and Equation (3) to calculate the resistivity of brass; record the result in Table 5. TABLE 5 Four Brass Wires slope l (m) ρ (Ω m) 0.24 Questions 1. Does the measured V-versus-I curve for the stainless-steel wire follow Ohm s law? 2. Based on the measurements on the four brass wires, what relationships can you draw for RR versus ll and RR versus AA? 3. If a brass wire is 4 cm long with a diameter of 1.3 cm, calculate its resistance? Determine the voltage drop over the brass wire for a 1.0 A current in the circuit. 8