FMB-DDSP Belt for High Load and Low Load Pulleys Flat, Positive Drive, Smooth & Impression Top Belt Material: Volta MB, Blue Coefficient of friction (Dry): Hardness: 95A / 46D Steel: 0.5 Temp. Range: -30 C to 60 C /-20 F to 140 F Stainless Steel: 0.5 Standard Width: 60 / 1524 mm UHMW: 0.28 Certification: FDA/USDA/USDA Dairy /EU Product: FMB -2.5 DDSP FMB-2.5 - DDSP ITO 50 FMB - 3 DDSP IRT Profile Surface Belt Weight (kg/ m 2 ): Belt Weight (lb/ ft 2 ): 4.34 kg/m² 0.889 lb/ft² 4.2 kg/m² 0.86 lb/ft² 4.85 kg/m² 0.993 lb/ft² Belt Min Pulley Diameter: Belt Min Pulley for Back Bending: 50 mm / 2 100 mm / 4 Belt Teeth Pitch: 20mm / 0.787"
DDSP Drive Pulleys for HIGH & LOW LOAD Applications. The Dual Drive Small Pulley Positive Drive belt can be used for both low load and high load applications. There are 2 series of pulleys that can be used with this belt, one is specifically suitable for using in high load (HL) applications and the other is designed for use in low load (LL) applications (see details in table below). It is essential that the correct pulley type is chosen in relation to the belts pulling force. The use of incorrect pulleys can cause a problem of disengaging. Max Pull Force for LL (low load) Pulleys Max Pull Force for HL (high load) Pulleys 1.5 kg/ cm width / 8.4 lb/ in width 4.5 kg/ cm width / 25.2 lb/ in width LOW LOAD (LL) DRIVE PULLEYS Pulley Outside Diameter (mm/ inch): Pulley Face Length (width - mm/ inch): HIGH LOAD (HL) DRIVE PULLEYS Pulley Outside Diameter (mm/ inch): Pulley Face Length (width - mm/ inch): 8 TEETH 10 TEETH 12 TEETH 14 TEETH 16 TEETH 48.81/ (1.92") 61.64/ (2.42") 74.46/(2.93") 87.29/(3.43") 100.12/(3.94") 25.4 /(1") 25.4 /(1") 25.4 /(1") 25.4 /(1") 25.4 /(1") 8 TEETH 10 TEETH 12 TEETH 14 TEETH 16 TEETH 51.1 /(2.01") 64.5 /(2.54") 77.9 /(3.06") 91.3 /(3.59") 104.7 /(4.12") 38 /(1.5") 38 /(1.5") 38 /(1.5") 38 /(1.5") 38 /(1.5") Standard Bore Size (Square) Both LL & HL : Pulley Locking Device Both LL & HL : 25 mm or 1 in. 40 mm or 1.5 Retainer ring Retainer ring Stainless Steel Wire locking collar Volta in-house fabricated flights are suitable for all of the above drive pulley sizes. Special pulley for Drum motors or center drive applications (24 teeth): This pulley has a large diameter that is especially designed for drum motors or center drive conveyors. Use the pulley where your drive system is located and small pulleys on the conveyor sides for tight transition between conveyors. Description: Pulley Outside Diameter : 151mm / 5.94 Number of teeth : 24 Maximum allowed teeth in mesh with the belt : 15 (225 Arc of contact) Pulley recommended material : UHMW (PE 1000)
Tail Pulleys: Volta may supply tail pulleys upon request, although it is not a standard item. Volta tail pulleys are smooth and the diameter is 9 mm (0.35") smaller than the drive pulleys to keep the belt height. A standard roller with bearings can be used as a tail pulley. The minimum pulley diameter for the tail pulley is 42 mm (1.65"). Pretension: It is recommended to apply slight pretension (up to 0.5%) to avoid slack around the drive pulley and prevent the belt teeth from disengaging. Recommended Conveyor Structure: Slide-bed with strips made of UHMW is the preferred construction in order to assure low coefficient of friction. The use of UHMW wall strips in order to prevent belt off-tracking. Support Rollers/strips on the return side of the belt (slack side). Volta drive pulley and Volta tail pulley every 4" - 6" (100-150 mm) between centers, according to the load. The drive pulleys must be made of UHMW. Smooth pulleys (without teeth) can be used on the tail side. The belt should be supported by the UHMW strips and should not exceed more than 2 (50 mm) from the UHMW strips on the outer sides of the conveyor. Tension device.
Belt Selection Procedure: 1. Calculate the belt Pull Force (Horizontal transport): F= fs*(g1+g2)+ fr*(g2+g3)+0.25*g4 F = Pull Force (kg) or (lb) fs = Coefficient of friction of belt on slide-bed fr = Coefficient of friction of the return rollers (bearings: fr =0.03, bushing: fr = 0.1 ) G1 = Maximum load on the conveyor (kg) or (lb) G2 = Belt weight (one direction) (kg) or (lb) G3 = Weight of supporting rollers (kg) or (lb) G4 = Maximum Accumulated Weight (kg) or (lb) (½ of total belt length) 2. Calculate the Allowed Pull Force according to number of teeth in mesh between the belt and the pulley: If number of teeth in mesh is less then 6, the max pull force must be corrected. Multiply the max pull force by K factor: Teeth in mesh K factor 6 or more 1 (180 Arc of contact at standard 12 teeth pulley) 5 0.8 (180 Arc of contact at standard 10 teeth pulley) 4 0.6 (180 Arc of contact at standard 8 teeth pulley) Fa = F max x K Fa = allowed pull force F max = maximum pull force for the belt (see table on page 2) K = correction factor according to number of teeth in mesh 3. Choose the belt width: Divide the calculated pull force by the belt width in order to get the pull force per unit width. Check that the calculated pull force per unit width is less than the maximum. Allow Pull Force according to the number of teeth in mesh for the belt (Fa). 4. Choose the pulley type by dividing the belt pull force (calculated in point 1 above), by the belt width. In accordance with the range of loads allowed for each pulley type as seen in the Pull Force table on Page 2. If 0 kg/cm< Pull Force <= 1.5kg/cm choose LL (Low Load pulley) If 1.5kg/cm < Pull Force < 4.5kg/cm choose HL (High Load pulley) Example: An UHMW slide bed conveyor transporting meat packages horizontally. Check if an 18" belt (450 mm) is suitable for this application and choose the drive pulley type (LL or HL). Given data: Package weight: 15 (lbs) 6.8 (kg) Maximum number of packages on belt: 15 15 Conveyor length: 10 (ft) 3.048 (m) Return rollers weight (bushing): 10 (lbs) 4.5 (kg) Number of return idlers: 3 3 Pulley diameter: 51.1 mm 2.01" (8 Teeth) Number of teeth in mesh: 8/2 = 4 8/2 = 4
Procedure: 1) Calculate the Pull force: Maximum load: G1= 15 * 15 = 225 (lbs) G1= 15 * 6.8 = 102 (kg) Belt weight - one direction: G2=0.889*(18/12)*10 G2= 4.34*0.45*3.048 G2= 13.3 lbs G2= 6 kg Return idler weight: G3= 3*10 =30 (lbs) G3 = 3*4.5 = 13.5 (kg) Accumulated weight: G4= 0 G4 = 0 F= fs*(g1+g2)+ fr*(g2+g3)+0.25*g4 F=0.28*(225+13.3)+0.1*(13.3+30) = 71 (lbs) Calculated Pull Force per inch width: 71/18 = 3.94lb./in. F=0.28*(102+6)+0.1*(6+13.5) =32.19 (kg) Calculated Pull Force per cm width: 32.19/45 = 0.71kg/cm 2) Allowed Pull Force according to number of teeth in mesh: For 8 teeth sprockets at 180 Arc of contact - 4 teeth in mesh K =0.6 (4 teeth in mesh) Fa =0.6*8.4 = 5.04 (lb/in) Fa = 0.6*1.5 = 0.9 (kg/cm ) 3) Belt width: Maximum allowed belt load: F(max) =5.04 * 18 = 90.7 (lbs) F(max) =0.9*45 =40.5 (kg) 18" belt width (45 cm) is suitable (the calculated pull force is less than the allowed pull force). 4) Drive Pulley Type Required. Pull Force per Belt Width: F = 32.19 (kg) / 45 (belt width, cm) = 0.71 kg/cm = 3.94 lb/inch In this case, the Pull Force is less than 1.5kg/cm or 8.4lb/inch, therefore, we must choose LL pulleys.