- The main function of the body structure is to protect occupants in a collision - There are many standard crash tests and performance levels - For the USA, these standards are contained in Federal Motor Vehicle Safety Standards (FMVSS) - They are FMVSS 208 (front), 214 (side), 301 (rear) and 216 (roof)
The insurance industry & consumer groups have their own test standard to evaluate vehicles beyond government standards For instance, the New Car Assessment Program (NCAP) It is based on the probability of injury; measured with a star rating where the five stars indicate lower probability of injury and vice-versa
FRONT BARRIER Is a condition of a moving vehicle crashes onto a rigid barrier at a front end Let s model the frontal impact with a point mass t = 0 t = 0, dx/dt = V0 t = 0, x = 0 dx/dt = 0 Resulting behavior of the point mass model The crush efficiency factor is used to consider non-uniform crash force properties
Example 1 Consider a vehicle of mass 1580kg impacting a rigid barrier at 55 km/h and average crush load of 300 kn. Calculate crash acceleration, deformation and time. Acceleration = -300000/1580 = 189.87 m/s^2 = -19.4g time = 1580 x 55/(3.6 x 300000) = 0.0805s Deformation = -300000 x (0.0805^2)/(2 x 1580) + (55/3.6) x 0.0805 = 0.614m
The crush efficiency factor is used to consider non-uniform crash force properties When crush factor approaching 1, it indicates the lower the head injury When designing the collapsed structure of the motor compartment, it is desirable to have a square wave shape
Procedure for establishing Front body structural requirements: 1. Maximum allowable cabin decelerations based on occupant injury 2. Consistent structural efficiency and crush space 3. Average and maximum allowable crush forces 4. Total crush forces to be used in the structural elements Crush force: 10% - hood & fender 20% - lower cradle 50% - mid-rail 20% - top of fender The front end elements are sized to ensure that the cabin zone won t be intruded
Example 2 a) Determine the required crush space. The structure will be 80% efficient and the allowable maximum deceleration is 20g. The impact speed is 48km/h. b) Compute the average total crush force with a vehicle mass of 1200kg and impact speed of 35 km/h. Solution: a) Crush space = (48/3.6)^2/(2*20*9.81*0.8) = 0.57m b) Crush force = 0.5*1200*(48/3.6)^2/0.57 = 187N
Beam sizing Beam section can be determined A thin-walled square section is subjected to an axial compressive load As the compressive load is gradually increased, the elastic buckling load is reached and the walls buckle As the load increases further and past the ultimate load, the walls section cripple and the load drops
Example 3 Each of motor compartment side rail must generate 25% of the crush force F=300kN. A 100mm square section is used. Find the required thickness for yield stress of 207 MPa. Solution: Pm = 0.25*300000 = 75000N Pm = 386*t^1.86*100^0.14*207^0.57 = 75000 t^1.86 = 4.88 t = 2.34mm
Motor compartment packaging typically require flange location & section shapes
Limit load analysis Is the ultimate load-carrying ability for the structure Is used to determine the failure load that cause to initiation of permanent deformation Plastic hinge model
Model with small deflection
Vehicle pitch during impact - Some vehicles rotate/pitch upon crash with a fixed barrier - It can increase the possibility of neck injuries - To reduce pitching, crushable beam is introduced
Example 4 Fup = 100000* 100/(400) = 25kN
Side impact - Plays an important role in sizing vehicle structure - FMVSS requires a minimum injury performance while NCAP uses star scale - The injury criterion is TTI index where the larger values indicate a more severe injury - TTI < 57 in desirable
Kinematic and load path analysis Final velocity Acceleration & time Distance traveled
Side impact model Time at which the occupant hit the door
Rear impact - To minimize fuel system from leakage Final speed Work of deformation Equivalent impact velocity Average rear crush force